A and B can do a piece of work in 3 days, B
and C in 4 days, C and A in 4 days. The time
taken by C alone to do it is :
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Work done by A and B in 1d= 1/3
Work done by B and C in 1d= 1/4
Work done by C and A in 1d=
1/4
Work done by 2(A,B and C) in 1d=1/3+1/4+1/4=10/11=5/6
Work done by A,B and C in 1d= (5/6)÷2=5/12
Work don by C alone in 1d= (Work done by A,B,C in 1d)-(Work done by B and C in 1d)
(5/12)-(1/3)=1/6
So,C alone takes 6 days to finish the work.
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