A and B can do a piece of work in 30 days and B and cc in 24 days . c and a in 40 days .How long will it take them to do the work together.
In what time can each finish it working alone
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Solution
Given :-
- A and B can do a piece of work in 30 days
- B and cc in 24 days
- c and a in 40 days .How
Find :-
- Time taken , if they work togather .
Explanation
According to question,
==> 1/A + 1/B = 1/30 ______(1)
And,
==> 1/B + 1/C = 1/24_______(2)
And,
==> 1/C + 1/A = 1/40_______(3)
Total working days , if they work togather
==> 2( 1/A + 1/B + 1/C) = 1/30 +1/24 + 1/40
==> 1/A + 1/B + 1/C = (4 + 5 + 3)/240
==> 1/A + 1/B + 1/C = 12/240
==> 1/A + 1/B + 1/C = 1/20
Since
- Total working days will be 20 days, if they work togather.
Now, Calculate working days of A's if they work alone
==> 1/A = 1/20- (1/B + 1/C)
==> 1/A = 1/20- (1/24)
==> 1/A = (6 - 5)/120
==> 1/A = 1/120
Similarly,
==> 1/B = 1/20 - (1/C + 1/A)
==>1/B = 1/20 - 1/40
==> 1/B = (2-1)/40
==> 1/B = 1/40
And,
==> 1/C = 1/20 - (1/A + 1/B)
==> 1/C = 1/20 - 1/30
==> 1/C = (3-2)/60
==> 1/C = 1/60
Hence
- A take working of days = 120 days
- B take working of days = 40 days
- C take working of days = 60 days
_________________
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