a and b can do a piece of work in 30 days, b and c in 20 days.. a starts the work and works on it for 5 days. then b takes it up and work for 15 days. finally c finishes the work in 18 days
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According to the question,
=A+B........30A+B........30days
=B+C.............20B+C.............20
=A........ 5
=B.........5+10
=C..........10+8
= Work done by(A+B) in 5 days
= 2×5=10
Work done by(B+C) in 5 days
= 10×3=30 work
Total work (finished till now)..........40 units
=Remaining work =60−40
= 20 units
= Here we find that C does remaining 20 units
in 8 days
C's efficiency = Work/Day=20 Work/8 Days=5/2
C's efficiency =5/2 unit/day
Therefore, time taken by C alone to complete the work =60/5×2=24 days
=A+B........30A+B........30days
=B+C.............20B+C.............20
=A........ 5
=B.........5+10
=C..........10+8
= Work done by(A+B) in 5 days
= 2×5=10
Work done by(B+C) in 5 days
= 10×3=30 work
Total work (finished till now)..........40 units
=Remaining work =60−40
= 20 units
= Here we find that C does remaining 20 units
in 8 days
C's efficiency = Work/Day=20 Work/8 Days=5/2
C's efficiency =5/2 unit/day
Therefore, time taken by C alone to complete the work =60/5×2=24 days
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