a and b can do a piece of work in 30 days both work together for 10 day and with help of C they finished the work in next 10 days if 3 days work of B equal to 2 days work of C then in how many days A will finish a work
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Step-by-step explanation:
(A+B)'s one day work = 130130
(B+C)'s one day work = 124124
(C+A)'s one day work = 120120
Adding, we get
2(A+B+C)'s one day work
=130+124+120=4+5+6120=15120=18130+124+120=4+5+6120=15120=18
(A+B+C)'s one day work = 18×12=11618×12=116
(A+B+C)'s 10 days work = 10×116=1016=5810×116=1016=58
Remaining work = 1−58=381−58=38
A's one day work = (A+B+C)'s one day work - (B+C)'s one day work
= 116−124=3−248=148116−124=3−248=148
In one day A can do
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