Question

A and B can do a piece of work in 36 days.B and C can do it in 60 days. A and C can do it in 45 days.How much time will C require to do it?​

Answer 1

Answer:

180 days .

Step-by-step explanation:

${\orange{\bold{Given : }}}$

$\ bold{A+B = 36 days }$

$\bold{B+C = 60 days }$

$\bold{A+C = 45 days }$

${\pink{\bold{Time \ C \ will \ take \ to \ do \ the \ work \ alone= ?}}}$

${\purple{\bold{Solution}}}$

We have to find the rate of work for each group of people for one day.

$\ bold{A+B = 36 days , 1 day = \frac{1}{36} }$

$\bold{B+C = 60 days , 1 day = \frac{1}{60}}$

$\bold{A+C = 45 days, 1 day = \frac{1}{45} }$

We have ,

$A + B + B + C + C + A = \frac{1}{36} + \frac{1}{60} + \frac{1}{45}$

Taking two as common :

$</em><em>2</em><em> </em><em>(</em><em>A</em><em> + B + C </em><em>)</em><em>= \frac{1}{36} + \frac{1}{60} + \frac{1}{45}$

$2 (A + B + C )= \frac{12}{180}$

$(A + B + C )= \frac{1}{30}$

A + B + C one day's work = 1/30

$\bold{C's \one \day's\ work = (Total\ work) - (A + B's \work) }$

$\bold{\frac{1}{30} - \frac{1}{36} }$

$\bold{\frac{6-5}{180} }$

$\bold{\frac{1}{180} }$

c alone can do the work in 180;days