A and B can do a piece of work in 36 days, B and C in 48 days, A and C can do this work in 72 days. In what time can they do it all working together?
Answers
Answer:
Total work is given by L.C.M of 72, 48, 36
Total work = 144 units
Efficiency of A = 144/72 = 2 units/day
Efficiency of B = 144/48 = 3 units/day
Efficiency of C = 144/36 = 4 units/day
According to the given data,
2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100
3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54
p = 198/16.5
p = 12 days.
Now, efficiency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day
(C+D) in p days = (4 + 6) x 12 = 120 unit
Remained part of work = (144-120)/144 = 1/6.
Answer:
32 days
Step-by-step explanation:
A and B’s one day’s work = 1/36. B and C’s one day’s work = 1/48. C and A’s one day’s work = 1/72.
If we add all this it will give us the work of 2A, 2B and 2C in 1 day i.e. (1/36) + (1/48) + (1/72) + (1/16)
That also implies that A, B and C’s one day’s work will be half of this i.e. (1/2) x (1/16) = (1/32)
From here it can found that they will complete the work in 32 days.