Math, asked by sabnamkhan29, 10 months ago

A and B can do a piece of work in 40 days, B and C can do it in 120 days. If B alone can do it in 180 days, in how many days will A and C do it together?​

Answers

Answered by menu28
2

Explanation:A + B take 40 days. B alone takes 180 days.

∴ A will take 1/40 – 1/180 = 7/360 ⇒ 360/7 days.

B + C take 120 days. ∴ C alone will take 1/120 – 1/180 = 1/360

i.e. 360 days. ∴ A & C together will take 7/360 + 1/360

= 8/360 ⇒ 360/8 = 45 days to complete the work.

Answered by Anonymous
6

Answer:

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Step-by-step explanation:

A + B take 40 days.

B alone takes 180 days.

∴ A will take 1/40 – 1/180 = 7/360

⇒ 360/7 days.

B + C take 120 days.

∴ C alone will take 1/120 – 1/180 = 1/360

i.e. 360 days.

∴ A & C together will take 7/360 + 1/360

= 8/360

⇒ 360/8 = 45

45 days to complete the work.

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