A and B can do a piece of work in 40 days, B and C in 30 days and C and A in 24 days (a) How long will it take them to do the work together? (b) In what time can each finish it working alone?
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Answer:
x/10
Step-by-step explanation:
Let Total work is = x
Given :
(A + B) takes 30 days to complete x work
=> work done by (A+B) in 1 day = x/30
(B+C) takes 24 days to complete x work
=> work done by (B+C) in 1 day = x/24
(A+C) takes 40 days to complete x work
=> work done by (A+C) in 1 day = x/40
work done by (A+B)+(B+C)+(A+C) in 1 day = x/30 + x/24 + x/40 = x(4+5+3)/120
work done by 2(A+B+C) in 1 day = 12x/120
= x/10
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