A and b can do a piece of work in 45 and 40 days respectively. They began to do the work together but a leaves after some days and then b completed the remaining work in 23 days. Find the number of days after which a left the work
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Answer:
AFTER 9 DAYS
Step-by-step explanation:
A completes the work in 45 days and B in 40 days.
Let the total work be LCM of 45 and 40 which is 360.
Efficiency of A=360/45 =8units
Efficiency of B=360/40 =9units.
Let number of days after which A left be x. Therefore, B worked for x+23 days.
8(x) + 9(x+23) =360
Solving this we get x= 9. A leaves the work after 9 days.
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