A and B can do a piece of work in 6days, B and C in 4 days, C and A in 8 days. In how many
days can A, B and C finishes it together? Also find the number of days in which B alone can
do the work,
Answers
Step-by-step explanation:
Time taken by (A+B) to finish the work = 6 days
Time taken by (B+C) to finish the work= 4 days
Time taken by (C+A) to finish the work = 8 days
: . (A+B)'s 1 days work = 1/6
(B+C)'s 1 days work = 1/4
(C+A)'s 1 days work = 1/8
Adding , we get
2(A+B+C) 's 1 days work = [ 1/6+1/4+1/8] =4+6+3/24=13/2
=> (A+B+C)'s 1 days work =(1/2*13/24) =13/48
=> A,B,C together can finish the work in 13/48 days
Now,A's 1 days
={(A+B+C)'s 1 days work} -{(B+C)'s 1 days work } =( 13/48-1/4) =1/48 days
Hence A can finish the work in 48 days .
B's 1 days work
={(A+B+C )'s 1 days work}-{(C+A)'s 1 days work}
=(13/48 -1/8) =7/48
Hence B can finish the work in 7/48 days
C's 1 days work
= {( A+B+C)'s 1 days work} -{(A+B )'s 1 days work }
=(13/48-1/6)=5/48
Hence ,c alone can finish the work in 5/48 days