A and B can do a piece of work in 72 days. B and C can do it in 120 days. A and C can do it in 90 days. In what
time can A alone do it?
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Answer:
120 Days
Step-by-step explanation:
Given that,
A+B=72 days, B+C=120 days, A+C=90 days.
So now calculate the Total Work by taking the L.C.M which is equal to 360.
Therefore, Total work = 360 unit…. (i)
Now we will get the one day work
A+B=5 unit work(360/72)…. (ii)
B+C=3 unit(360/120)…. (iii)
A+C=4 unit(360/90)…. (iv).
By adding these we get,
2(A+B+C)=12 unit
A+B+C=6 unit…. (v)
Now from (iii) and (v) we'll get the A's one day work, which is equal to 3 unit
A=3 unit…. (vi)
Now from (i) and (vi) we'll get the days that A can complete the work alone.
i.e, 360/3= 120 days.. Ans
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