A and B can do a piece of work in 8 days ,B and c can do the same work in 12days and
A,B,C complete it in 12 days and A,B,C complete it in 6 days . In how many days A and C
finish it?
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Answer:
We will solve this question using the LCM technique.
A+B=8 Days; B+C=12 Days; A+B+C=6 Days.
So, let the TOTAL WORK be 24 Parts.
Note: 24 is the LCM of 8, 12 & 6.
So, A+B complete 3 parts per day.
B+C complete 2 parts per day.
A+B+C complete 4 parts per day.
Now, 2(A+B+C)−(A+B)−(B+C)=(A+C)
=>(A+C)=2(4)−3−2
=>(A+C)=3 parts per day.
A & C will take 8 days to complete
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