A and B can do a piece of work in eight days and B alone can do it in 16 days. In how many days, can A do it alone?
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A alone can do
8
1
−
12
1
=
24
3−2
=
24
1
of the work in 1 day, i.e., A alone can do the same work in 24 days.
B's 1 day's work =
12
1
⇒B's 4 day's work =
12
4
=
3
1
∴ Remaining
3
2
of the work is done by A alone in
3
2
×24=16 days
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