A and B can do a piece of worked in 16 and 12 days respectively, with the help of C they complete the work in 4 days, how much will C alone take to complete the remaining work
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Answer:
8 days
Step-by-step explanation:
A's 1 day work = 1/16
B's 1 day work = 1/12
(As A worked for 2 days alone we'll find work done by A in 2 days by multiplying his one day work by 2)
A's 2 day work = 2x(1/16) =1/8
Remaining work = 1–1/8 =7/8
( Total work is always presumed to be 1 in all such cases )
Now this remaining work will be done by A and B together .
(A+B)'s 1 day work = (1/16) + (1/12) = 7/48
A and B together can do the remaining work in = (7/8)÷(7/48) = 6 days
Total time taken = 6+2 = 8 days ANS
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