A AND B CAN DO A WORK IN 10 DAYS, B AND C CAN DO THAT WORK IN 15 DAYS . C AND A CAN DO THAT WORK IN 20 DAYS. SO FIND HOW MANY DAYS WILL C ALONE TAKE TO DO THAT WORK
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B's 5 days work =101×5 =21
Remaining work =1−21 =21
c can finish work =15×21 =7.5 days
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(a+b) x 10 = (b+c) x 15= (c+a) x 20 = work=60 units
a+b= 1/10 work= 6 units
b+c=1/15 work=4 units
c+a=1/20 work =3units
2a+2b+2c=13 units
a+b+c=6.5 units
c=6.5-6=0.5units
number of c days= 60/0.5=120
120 days? That doesn't seem right.
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