a and b can do a work in 15 days. After 11 days of starting the work a left the work and b finished the work in 24 days. Now, calculate how many time they will take to do the same work separately?
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Step-by-step explanation:
Given, A and B can complete a work in 15 days and 10 days respectively.
=> The amount of work done by them together in 1 day = 1/15 + 1/10
= (2+3)/30 = 5/30 = 1/6
Given, they worked together for 2 days.
=> The amount of work done by them together = 2*(1/6) = 1/3
The amount of work to be completed by A alone = 1 - 1/3 = 2/3
The number of days taken by A alone to complete the remaining work = (2/3)/(1/15) = 30/3 = 10
=> The whole work was completed in (2+10) i.e., 12 days.
Let total work = LCM(15,10)= 30 units
hope it is helpful
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