Question

A and B can do a work in 34/3 days, working alternatively
with B working first. A can complete the work alone in
48 days. In how many days, B does 4 times of the same
work
A>20 days
B>30 days
C>27 days
D>33
days​

Answer 1

Answer:

C) 27 days

Step-by-step explanation:

A completes the work alone in 48 days.

So , A's one day work is 1 / 48 of total work.

B's work in one day = 8 / ( 9 x 6 ) = 4 / 27

Therefore , B can complete the total work alone in 27 / 4 days.

So , B can do 4 times work in 27 days .