A and B can do a work individually in 11 and 33 days respectively. In how many days can they complete the work, working alternatively?
Answers
The LCM of 11 & 33 is 33
A can do 3 parts in a day and B can do 1 parts in a day. So 4 parts in a dayboth A and B can do as combined. working individually they need 4 days each so it will be 16.5
A can do the work in 11 days
1 day = 1/11 of the work
B can do the work in 33 days
1 day 1/33 of the work
Amount of work A and B can do in 2 days:
2 days = 1/11 + 1/33 = 4/33
Find the number of 2 days both A and B alternate to work
Number of 2 days = 33/4 = 8.25 => 8 days
Number of days = 8 x 2 = 16
Find the amount of work left:
Amount of work left = 1 - (8 x 4/33) = 1/33
Find the amount of time A need to complete the remaining work:
Number of days = 1/33 ÷ 1/11 = 1/3 day
Find the number of work:
Number of days = 16 + 1/3 = 16 1/3 days
Answer: They will need 16 1/3 days to complete the work.