Question

A and B can do job in 25days. After 15 days of working together, B leaves. If A completes the remaining part of the job in 20days, how long would each take to complete the job, working separately

Answer 1

Answer:

(A+B)'s one day work = 1/25

amount of work completed in 15 days = 15x1/25

= 3/5

remaining work = 1-3/5 = 2/5

according to the question,

A finish the remaining 2/5 part of the work in 20 days.

therefore, time taken by A to finish the work alone = 20÷2/5 = 50 days

now,

A's one day work + B's one day work = (A+B)'s one day work

1 / A + 1 / B = 1/25

1/50 + 1 / B = 1/25

1 / B = 1/25 - 1/50

1 / B = 1/50

therefore, time taken by B to complete the whole work = 50 days

Step-by-step explanation:

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