Math, asked by yuganterji, 1 year ago

A and B can do some work in 10 days.B and C can do the same work in 20 days and C and A will complete the work in 12 days.How long will each take to complete the work alone?
EXPLAIN.....

Answers

Answered by lynalam0005
0

A and B → 15 days


A → 20days


So, let's take LCM of 15 and 20. That's 60.


Remember: This 60 unit is the total work to be done.


So, A and B do (60/15) = 4 unit work/day …(1)


And, A does (60/20) = 3 unit work/day …(2)


(1)-(2) gives


B does (4–3)= 1 unit/day


So, Total days req. = (Total work)/unit per day


i.e, B can do it in (60/1)=60 days.

Answered by sohammatani2207
0

Answer:

A and B can do a piece of work in one day = 1/10

B and C can do a piece of work in one day = 1/20

C and A can do a piece of work in one day = 1/12

together

2(A+B+C) = 1/10+ 1/20+1/12

= 6+3+5/60

= 14/60 = 7/30

2(A+B+C) =7/30

(A+B+C) =7/30×1/2=7/60

(A+B+C) - (A+B) = C

7/60 - 1/10 = 7-6/60= 1/60

(A+B+C) - (B+C) = A

7/60 - 1/20 = 7-3/60= 4/60= 1/15

(A+B+C) - (C+A) = B

7/60 - 1/12 = 7-5/60= 2/60= 1/30

A can complete the work in 15 days

B can complete the work in 30 days

C can complete the work in 60 days

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