A and B can do some work in 10 days.B and C can do the same work in 20 days and C and A will complete the work in 12 days.How long will each take to complete the work alone?
EXPLAIN.....
Answers
A and B → 15 days
A → 20days
So, let's take LCM of 15 and 20. That's 60.
Remember: This 60 unit is the total work to be done.
So, A and B do (60/15) = 4 unit work/day …(1)
And, A does (60/20) = 3 unit work/day …(2)
(1)-(2) gives
B does (4–3)= 1 unit/day
So, Total days req. = (Total work)/unit per day
i.e, B can do it in (60/1)=60 days.
Answer:
A and B can do a piece of work in one day = 1/10
B and C can do a piece of work in one day = 1/20
C and A can do a piece of work in one day = 1/12
together
2(A+B+C) = 1/10+ 1/20+1/12
= 6+3+5/60
= 14/60 = 7/30
2(A+B+C) =7/30
(A+B+C) =7/30×1/2=7/60
(A+B+C) - (A+B) = C
7/60 - 1/10 = 7-6/60= 1/60
(A+B+C) - (B+C) = A
7/60 - 1/20 = 7-3/60= 4/60= 1/15
(A+B+C) - (C+A) = B
7/60 - 1/12 = 7-5/60= 2/60= 1/30
A can complete the work in 15 days
B can complete the work in 30 days
C can complete the work in 60 days