A and b can do the piece of work in 12 days b and c in 15 days c and a in 20 days find the number of days if a can do the same work
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Step-by-step explanation:
A+B = 12
B+C = 15
A+C = 20
Lcm of (12,15,20) = 60
Efficiency is
A+B = 5
B+C = 4
A+C = 3
Total efficiency
2 (A+B+C) = 12
A+B+C = 6
Individual efficiency
A = 6 - 4 = 2
B = 6 - 3 = 3
C = 6 - 5 = 1
Individual time taken
A = 60/2 = 30 days
B =60/3 = 20 days
C = 60/1 = 60 days
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