Question

A and b can do the piece of work in 12 days b and c in 15 days c and a in 20 days find the number of days if a can do the same work

Answer 1

Answer:

Step-by-step explanation:

A+B = 12

B+C = 15

A+C = 20

Lcm of (12,15,20) = 60

Efficiency is

A+B = 5

B+C = 4

A+C = 3

Total efficiency

2 (A+B+C) = 12

A+B+C = 6

Individual efficiency

A = 6 - 4 = 2

B = 6 - 3 = 3

C = 6 - 5 = 1

Individual time taken

A = 60/2 = 30 days

B =60/3 = 20 days

C = 60/1 = 60 days