A and B can do work in3days,B and C in 4 days,C and A in 4 days.the time taken by c alone to do it is
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A and B can do work in 3 days,B and C in 4 days,C and A in 4 days.the time taken by c alone to do it is
Step-by-step explanation:
Work done by A+B in 1 day = 1/3 of complete work
Work done by B+C in 1 day = 1/4 of complete work
Work done by C+A in 1 day = 1/4 of complete work
,Then work Done be A+B+B+C+C+A =
2(A+B+C) = 1/3+1/4+1/4 (because every worker comes twice in the given question)
2(A+B+C) = (1/3)*4+(1/4)*3+(1/4)*3
2(A+B+C) = 4/12+3/12+3/12
2(A+B+C) = 10/12
A+B+C = (10/12)/2
A+B+C = 10/12 * 1/2
A+B+C = 5/12
We will subtract work done by A+B in 1 day from work dome by A+B+C in 1 day
, 5/12 - 1/3 = 5/12*1 - 1/3*4 = 5/12 - 4/12 = 1/12
Work done by C in 1 day = 1/12
C alone can complete work in 12 days
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