A and B can finish a piece of work in 12 days.if A alone can finish the same work in 20 days in how many days B alone can finish it
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a+b=12
a=20
lcm=60
efficiency of a=3
a+b=5
so b=5-3=2
so no of days for b =60/2=30 days...
a=20
lcm=60
efficiency of a=3
a+b=5
so b=5-3=2
so no of days for b =60/2=30 days...
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