A and B can finish a piece of work in 15
days , B and C can do it in 20 days and C and
A in 30 days How long would each take to
finish the work alone ?
(3 Points)
A in 40 days B in 24 days and C in
120 days
A in 24 days B in 40 days and C in
120 days
A in 120 days B in 24 days and C in
40 days
none
Answers
Answered by
0
Answer:
T-10 ,alone ->30,20,60
Step-by-step explanation:
T.W = L.C.M(12,15,20) = 60 units
their efficiency,
a+b--> 60/12 = 5 units/day
b +c=>60/15 = 4 '" "
c + a =>60/20 = 3 " "
(a+b+c) =12/2 = 6 units/day
a alone => 2u/day & b alone=> 3u/day
& c alone 1u/day
together = 60/6 = 10 days
separately a = 60/2 = 30 days
& b = 60/3 = 20 days & c=60/1 = 60 days
Answered by
0
Step-by-step explanation:
ANSWER
A+B(1day
′
s)=
12
1
work
B+C(1day
′
s)=
15
1
work
A+C(1day
′
s)=
20
1
work
Adding all the above,
2(A+B+C)(1day
′
s)=
12
1
+
15
1
+
20
1
=
60
5+4+3
=
60
12
=
5
1
work
∴A+B+C(1day
′
s)=
10
1
work
∴C(1day
′
s)=(A+B+C)(1day
′
s)−(A+B)(aday
′
s)
=
10
1
−
12
1
=
60
6−5
=
60
1
Hence, C can complete the whole work in 60 days.
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