a and b can finish a piece of work in 16 days and 12 days respectively. a started the work and worked at it for 2 days . he was then joined by b . find the total time taken to finish the work.
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Answered by
13
hyy dear Afinishes the work in 16 days....
A finishes 1/16 of the work in one day.
A had worked for two days= 2*1/16 = 1/8
the work left after A has worked for two days = 1- 1/8 = 7/8
B finihses the work in 12 days
in 1 day B finishes 1/12 of the work.
A and B togeher in one day can finish= 1/16+1/12 = (3+4)/48= 7/48 of work
A and B together can complete the remaining work= (7/8) / (7/48)= 7*48/8*7 = 6 days.
therefore total time taken = 2 days by A alone + 6 days by both Aand B = 8 days.
A finishes 1/16 of the work in one day.
A had worked for two days= 2*1/16 = 1/8
the work left after A has worked for two days = 1- 1/8 = 7/8
B finihses the work in 12 days
in 1 day B finishes 1/12 of the work.
A and B togeher in one day can finish= 1/16+1/12 = (3+4)/48= 7/48 of work
A and B together can complete the remaining work= (7/8) / (7/48)= 7*48/8*7 = 6 days.
therefore total time taken = 2 days by A alone + 6 days by both Aand B = 8 days.
ishika58:
i think it is not accurate
Answered by
7
A can finish a piece of work in 16 days
so he can compete 1/16 part of work in a day
similarly B can complete 1/12 part of work in a day
they together can complete 1/16+1/12
=3+4/48
=7/48
A worked for two days means he completed 2/16=1/8 part of work
remaining work=1-1/8
=7/8
hence They worked together
7/8÷7/46
=6
they worked for 6 days
so they finished work in 6+2=8 days
so he can compete 1/16 part of work in a day
similarly B can complete 1/12 part of work in a day
they together can complete 1/16+1/12
=3+4/48
=7/48
A worked for two days means he completed 2/16=1/8 part of work
remaining work=1-1/8
=7/8
hence They worked together
7/8÷7/46
=6
they worked for 6 days
so they finished work in 6+2=8 days
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