Question

A and B can finish a piece of work in 16 days and 12 days respectively. A started the work and worked at it for 2 days. He was then joined by B. Find the total time taken to finish the. work.

Answer 1

Do it LCM METHOD.
A= 16 D
B = 12 D
SO LCM OF 12 AND 16 IS 48. SO THAKE THE WHOLE WORK AS 48 UNITS.
NOW.
A CAN 3 Units / day and B can 4 units / day.
A started the work and works for 2 day so . 6 units WORK IS DONE. SO REST WORK IS 48-6= 42 UNITS. NOW A AND B BOTH COMPLIT THE WORK. SO 1 DAY WORK OF A AND B IS 3+4= 7 UNITS. SO TIME IS NEED = 42/7= 6 DAY.
SO TOTAL DAY TO COMPLITE THE WORK IS = 6+2 DAY = 8 DAY. IT IS LCM METHOD. IF U DONT UNDERSTAND THEN MESSAGE ME. I WILL DO IT OTHER METHOD. IF THIS METHOD IS HELFFUL. THEN MARK AS BARINLIST PLEASE

Answer 2

$\bold{Answer}$

For average work we have to find the LCM.

SO, $\textbf{\underline{LCM of 12 and 16 is 48}}$

$\boxed{\textbf{Case 1}}$

For A,

Work done in one day =48/16 =3

$\boxed{\textbf{Case 2}}$

For B,

Work done in one day = 48/12 = 4

According to the question,

A has done work for 2 days

so, 2×3 = 6

Remaining days = 46 (because A has done work for 2 days.)

A+B can do 7 works together (4+3 =7 )

Therefore , 42 / 7 = 6

(48-6 =42)

$\bf{\textbf{Total time} \longrightarrow (6 + 2) = 8}$