A and B can finish a piece of work in 20 days . B and C in 30days and C and A in 40 days . in how many days will A alone finish the job? a) 36 days b)48 days c(30 days d)40 days
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(A+B) 's 1 day work = 1/20
(B+C)'s. 1 day work=1/30
(C+A) 's 1 day work=1/40
TOGETHE ADDING 2(A+B+C) = (1/20+1/30+1/40)
=(6+4+3/120)
=(13/120)
THEREFORE,(A+B+C)'s 1 day work=1/2×13/120
=13/240
A's 1 day work = 13/240-1/30
=13-8/240
=5/240
=1/48
THEREFORE A Alone can do the work in 48 days
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