Math, asked by jothika132002, 7 months ago

A and B can finish a piece of work in 20 days . B and C in 30days and C and A in 40 days . in how many days will A alone finish the job? a) 36 days b)48 days c(30 days d)40 days ​

Answers

Answered by pawan578
0

ANSWER

(A+B) 's 1 day work = 1/20

(B+C)'s. 1 day work=1/30

(C+A) 's 1 day work=1/40

TOGETHE ADDING 2(A+B+C) = (1/20+1/30+1/40)

=(6+4+3/120)

=(13/120)

THEREFORE,(A+B+C)'s 1 day work=1/2×13/120

=13/240

A's 1 day work = 13/240-1/30

=13-8/240

=5/240

=1/48

THEREFORE A Alone can do the work in 48 days

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