Math, asked by mathewsurani2, 4 months ago

a and b can finish a piece of work in 6 2/3 days a can do the job by herself in 12 days if b wanted to do the job alone how long would it take her​

Answers

Answered by GAMINGDEMON
0

Step-by-step explanation:

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Answered by Dd19
1

Answer:

15 days

Step-by-step explanation:

Days A and B took to complete work together= 6 2/3 = 20/3

Work done by A and B in one day = 1/ (20/3) = 3/20

A took 12 days to complete the same work

Work done by A in one day = 1/12

A+B = 3/20

1/12 + B = 3/20

B = 3/20 - 1/12

B = (36-20)/(20*12)

B = 16/(20*12)

B = 1/15

work done by B in one day = 1/15

Therefore B takes 15 days to complete the same work

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