Math, asked by geetanjalikasgar, 1 day ago

A and B can finish a piece of work in 6 days and 10 days respectively begin the work and worked at it for 2 days he was then joined by b find the total time taken to complete the work ?​

Answers

Answered by XxitzMichAditixX
2

Answer:-

Explanation:

Let the breadth of the wall be x metres.

Then, Height = 5x metres and Length = 40x metres.

x * 5x * 40x = 12.8

=>x3 =12.8/200 = 128/2000 =64/1000

=> x = 4/10 m

=> x = (4/10)*100 = 40 cm

hope it helps ♡

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Answered by soniyamohite52
2

Answer:

= 18/5 days

Step-by-step explanation:

Given that A can finish a piece of work in 6 days,

So, in one day A will do 1/6 th of work,

Given that B can finish a piece of work in 4 days,

So, in one day B will do 1/4 th of work,

Given that initially A has worked for 2 days,

So A will complete 2*1/6 = 1/3 rd of work

Remaining Work = 2/3 rd of work.

If A and B works together,

In 1 day, bot A and B could do = (1/6 + 1/4) of work

= 5/12 th of work

So, 2/3 rd of work requires 2/3*1/(5/12)

= 8/5 days,

Total time , to finish the work

= Time A working alone an Time taken when both A and B are

working together

= 2 + 8/5

= 18/5 days

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