A and B can finish a piece of work in 6 days and 4 days respectively .A started work and worked for 2 days and then he joined to B . Find the total time taken to finish the work
Answers
Answered by
8
Hope its help u...
Answer:18/5 of days
Answer:18/5 of days
Attachments:
Answered by
8
Solution:
Given,
A can finish a piece of work in 6 days,
Hence, In 1 day A will do 1/6 part of work,
B can finish a piece of work in 4 days,
Hence, In 1 day B will do 1/4 part of work,
Given ,
Firstly A has worked for 2 days,
Hence A will complete 2 × 1 / 6 = 1 / 3 part of work
So, Remaining Work = 2/3 part
In Condition, If A and B works together,
In 1 day,
Together A and B could do = (1/6 + 1/4) of work
= 5/12 part of work
Hence, 2/3 part of work requires 2/3 × 1/(5/12)
= 8/5 days,
=> Total time To finish the work
Working together:
= 2 + 8/5
= 18/5 days
Hence, the required total time taken to finish the work is 18 / 5 days.
Hope You Understand !
Given,
A can finish a piece of work in 6 days,
Hence, In 1 day A will do 1/6 part of work,
B can finish a piece of work in 4 days,
Hence, In 1 day B will do 1/4 part of work,
Given ,
Firstly A has worked for 2 days,
Hence A will complete 2 × 1 / 6 = 1 / 3 part of work
So, Remaining Work = 2/3 part
In Condition, If A and B works together,
In 1 day,
Together A and B could do = (1/6 + 1/4) of work
= 5/12 part of work
Hence, 2/3 part of work requires 2/3 × 1/(5/12)
= 8/5 days,
=> Total time To finish the work
Working together:
= 2 + 8/5
= 18/5 days
Hence, the required total time taken to finish the work is 18 / 5 days.
Hope You Understand !
Similar questions