Math, asked by diddivarunteja889, 6 months ago

A and B can finish a Piece of work in 6and 10 days respectively . A began the work and worked at it for 2 days . he was Then joined by B. Find the tot el time taken to Complete the work

Answers

Answered by Anonymous
4

Answer :

›»› The total time taken to complete the work is 4.5 days.

Given :

  • A and B can finish a Piece of work in 6and 10 days respectively . A began the work and worked at it for 2 days . he was Then joined by B.

To Find :

  • The total time taken to complete the work.

Solution :

Let us assume that, the work is x.

→ Work done A in one day = x/6

→ Work done by B in one day = x/10

→ Work done by A in two days = 2x/6

→ Work done by A and B in one day = x/6 + x/ 10

→ Work done by A and B in one day = 8x/30

→ Work left = x - 2x/6

Time taken by both A nad B,

→ 4x/6 ÷ 8x/30

→ 2x/3 ÷ 8x/30

→ 2x/3 ÷ 4x/15

→ 2x/3 * 15/4x

→ 2x * 5/4x

→ 5/2

2.5

Now,

→ Total time = 2.5 + 2

→ Total time = 4.5

Hence, the total time taken to complete the work is 4.5 days.

Answered by Anonymous
1

\blue{\bold{\underline{\underline{Answer:}}}}

 \:\:

 \green{\underline \bold{Given :}}

 \:\:

  • A can finish work in 6 days

 \:\:

  • B can finish work in 10 days

 \:\:

  • A started work 2 days before B

 \:\:

 \red{\underline \bold{To \: Find:}}

 \:\:

  • Total time taken to complete the work

 \:\:

\large{\orange{\underline{\tt{Solution :-}}}}

 \:\:

Let the total days required be "x"

 \:\:

 \underline{\bold{\texttt{One day work of A :}}}

 \:\:

\purple\longrightarrow  \sf \dfrac { 1 } { 6 }

 \:\:

 \underline{\bold{\texttt{One day work of B :}}}

 \:\:

\purple\longrightarrow  \sf \dfrac { 1 } { 10 }

 \:\:

 \purple{\underline \bold{According \: to \: the \ question :}}

 \:\:

  • A works from the very beginning , So A will work for (x) days

 \:\:

  • B works 2 days less than A , So B works for (x - 2) days

 \:\:

 \sf \longmapsto 1 = \dfrac { 1 } { 6 } \times (x) + \dfrac { 1 } { 10 } \times (x - 2)

 \:\:

 \sf \longmapsto 1 = \dfrac { 5x + 3x - 6} { 30 }

 \:\:

 \sf \longmapsto 1 = \dfrac { 8x - 6 } { 30 }

 \:\:

 \sf \longmapsto 30 = 8x - 6

 \:\:

 \sf \longmapsto 30 + 6 = 8x

 \:\:

 \sf \longmapsto x = \dfrac { 36 } { 8 }

 \:\:

 \bf \dashrightarrow 4.5

 \:\:

  • Hence total days required to complete the work is 4.5
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