A and B can finish a Piece of work in 6and 10 days respectively . A began the work and worked at it for 2 days . he was Then joined by B. Find the tot el time taken to Complete the work
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Answer :
›»› The total time taken to complete the work is 4.5 days.
Given :
- A and B can finish a Piece of work in 6and 10 days respectively . A began the work and worked at it for 2 days . he was Then joined by B.
To Find :
- The total time taken to complete the work.
Solution :
Let us assume that, the work is x.
→ Work done A in one day = x/6
→ Work done by B in one day = x/10
→ Work done by A in two days = 2x/6
→ Work done by A and B in one day = x/6 + x/ 10
→ Work done by A and B in one day = 8x/30
→ Work left = x - 2x/6
Time taken by both A nad B,
→ 4x/6 ÷ 8x/30
→ 2x/3 ÷ 8x/30
→ 2x/3 ÷ 4x/15
→ 2x/3 * 15/4x
→ 2x * 5/4x
→ 5/2
→ 2.5
Now,
→ Total time = 2.5 + 2
→ Total time = 4.5
Hence, the total time taken to complete the work is 4.5 days.
Answered by
1
- A can finish work in 6 days
- B can finish work in 10 days
- A started work 2 days before B
- Total time taken to complete the work
Let the total days required be "x"
- A works from the very beginning , So A will work for (x) days
- B works 2 days less than A , So B works for (x - 2) days
- Hence total days required to complete the work is 4.5
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