Question

A and B can finish a piece of work together in 24 days both work together for 20 days and after that B left the work and the total work is completed in 26 days .In how many days B alone can finish that work​

Answer 1

Answer:

(M+B)24 is Total Work. => (M+B)24 = (M+B)20 + (M)6 [Because now total work is completed in 26 days (Man alone does the work for last 6 ...

Top answer ·

Answer 2

$Answer: IN \: 36 \: DAYS \:$

Solution

If both A and B can complete the work In 24 days than there 1 day work will be 1/24

Now they do work for 20 days

There 20days work will be 20/24

remaining work -1/6

let be can do whole work in X days than his 1 day work =1/x

Now accoridng to question work is completed in 26 days this means B alone do work for 6 days. Hence:-

$\huge\frac{1}{x} \times 6 = \frac{1}{6}$

$\huge \: x = 6 \times 6 = 36$

Answer - 36 days

Additional information

• If one total time to complete work is given than flip the time to obtain one day work