A and B can finish a work in 10 days while B and C can do it in 18 days. A started the work, worked for 5 days, then B worked for 10 days and the remaining work was finished by C in 15 days. In how many days could C alone have finished the whole work?
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1
Answer:
45 Days
Step-by-step explanation:
Let 'C' complete the work in x days.
Work done by (A + B) in 1 day =
110 work
Work done by (B + C) in 1 day =
118 work
A's 5 day's work + B's 10 day's work + C's 15 day's work
= 1
510+518+10x = 1
=> x = 45 days.
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