A and B can finish a work in 16 days. A started the work and worked at it for 2 days. He was then joined by B. Find the total time taken to finish the work.
Answers
Answer:
8days
Step-by-step explanation:
Average work=48(LCM of 16 and 12)
A does 48 work in 16 days
In 1 day 48/16=3work
B does 48 work in 12 days
In 1 day 48/12=4work
A done work for 2 days
So,work done by A 8n 2 days=2×3=6
Remaining work is 42
A+B together can do 7 work in a day
Thus,42/7=6days
Total days 6+2=8days
Answer:
8 days
Step-by-step explanation:
A's 1 day work = 1/16
B's 1 day work = 1/12
(As A worked for 2 days alone we'll find work done by A in 2 days by multiplying his one day work by 2)
A's 2 day work = 2x(1/16) =1/8
Remaining work = 1–1/8 =7/8
( Total work is always presumed to be 1 in all such cases )
Now this remaining work will be done by A and B together .
(A+B)'s 1 day work = (1/16) + (1/12) = 7/48
A and B together can do the remaining work in = (7/8)÷(7/48) = 6 days
Total time taken = 6+2 = 8 days ANS
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