Math, asked by Ganeava2805J, 9 hours ago

A and B can finish a work in 16 days. A started the work and worked at it for 2 days. He was then joined by B. Find the total time taken to finish the work.​

Answers

Answered by hoskinsgavin12
0

Answer:

8days

Step-by-step explanation:

Average work=48(LCM of 16 and 12)

A does 48 work in 16 days

In 1 day 48/16=3work

B does 48 work in 12 days

In 1 day 48/12=4work

A done work for 2 days

So,work done by A 8n 2 days=2×3=6

Remaining work is 42

A+B together can do 7 work in a day

Thus,42/7=6days

Total days 6+2=8days

Answered by jyotibhavyamishra
0

Answer:

8 days

Step-by-step explanation:

A's 1 day work = 1/16

B's 1 day work = 1/12

(As A worked for 2 days alone we'll find work done by A in 2 days by multiplying his one day work by 2)

A's 2 day work = 2x(1/16) =1/8

Remaining work = 1–1/8 =7/8

( Total work is always presumed to be 1 in all such cases )

Now this remaining work will be done by A and B together .

(A+B)'s 1 day work = (1/16) + (1/12) = 7/48

A and B together can do the remaining work in = (7/8)÷(7/48) = 6 days

Total time taken = 6+2 = 8 days ANS

HOPE IT HELP....

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