Question

A and B can finish a work in 8 days. They worked together for 5 days and then B left. The work was finished after 6 more days. In how many days can B alone finish the work?​

Answer 1

According to question

A+B complete work in 30 days

Take L.C.M of (A+B)'s time to calculate the total work Assume total work 30 units

Hence,

(A+B)'s work/day = 1 Unit/day

(A+B)'s 20 day's work = 20x1 unit/day = 20 units

Rest work = 30−20=10 units

Now, Rest work done by A in 20 days

Then one day's work of A =1020=12

Total work done by A in=3012=60days

Step-by-step explanation:

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