Question

A and B can paint the fence of a park in 8 days, B and C can paint the fence in 12 da
C and A can paint the fence in 6 days. In how many days will (i) each one of the
the fence, (ii) all of them working together paint the fence?​

Answer 1

Answer:

A+B one day work=1/8

B+C one day work= 1/12

C+A one day work= 1/6

adding all equation

2(A+B+C) one day work= 1/8+1/12+1/6

= 3+2+4/24

=9/24

A+B+C one day work=9/24*2=9/48

= 3/16

A+B+C complete work in 16/3days

A one day work = A+B+C one day work- B+C one day work

A one day work = 3/16 -1/12=9-4/48

=5/48

A complete work in 48/5

similarly

B one day work =3/16 -1/6=9-8/48

=1/48

B complete work in 48 days

similarly

C one day work =3/16 -1/8

C one day work =3-2/16=1/16

C complete work in 16 days