A and b can separately do a piece of work in 20 and 15 days, respectively. They worked together for 6 days, after which b was replaced by
c. If the work was finished in the next 4 days, then the number of days in which c alone could do the work will be
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Answer:
40 DAYS
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A can do in 20 days 1 part of work.
A can do in 1 day 1/20 part of work.
B can do in 15 days 1 part of work.
B can do in 1 day 1/15 part of work.
In 1 days they total do (1/20+1/15) = 7/60 part of work.
In 6 days they do = 7/60 * 6 = 7/10 part of work.
Work remaining = (1 - 7/10) = 3/10 part of work.
C do 3/10 part of work in 4 days.
C can do 1 part of work in = 4÷ (3/10) = 13.3.......days.
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