A and B can separately do a work in 10 and 15 days respectively. They worked together for some days and then A completed the work in 5 days. For how many days had A and B worked together
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Given,
A can do a work in = 10 days
B can do a work in = 15 days
A’s, 1 day's work = 1\10 ... (1)
B’s, 1 day's work = 1\15
(A+B)’s 1 day's work = 1 \10+ 1\15 = 3+2\30 = 5\30=1\6
Now, let us consider (A+B) worked together for x days.
So, (A+B)’s, x day work = x\6
Remaining work =1− x\6
It is given that,
A can do the remaining work, (1− x\6)in =5days
So, A’s 1 day's work = 6-x\30... (2)
From (1) and (2), we get
1\10=6−x\30⇒ 30\10 =6−x
⇒3=6−x
⇒x=6−3=3
∴ Both A and B can do the work together in 3 days.
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