A and B can together buil a wall in 25 days. They work together for 15 days and then B goes away. A finishes the rest of work in 20 days. How long would each take to finish the work separately
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Answer:
50 days.
(A+B)'s 1 day work=1/25.
(A+B)'s 15 days work=15/25.
Then B left.
Remaining work=1-15/25=10/25.
So, it takes A 20 days to complete 10/25 part of work.
So, number of days required by A to complete the work = 20*25/10=50.
So, A's 1 day work=1/50.
Had A and B been working for 25 days they would've completed the work.
A's 25 days work=25/50.
So, B's 25 days work =25/50 = 1/2 of total work.
Therefore, to complete the entire work, B needs 25*2=50 days.
Hope this helps.
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Answer:
35
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