Math, asked by msmanoharsingh1949, 8 months ago

A and B can together buil a wall in 25 days. They work together for 15 days and then B goes away. A finishes the rest of work in 20 days. How long would each take to finish the work separately​

Answers

Answered by sharmagaurav18k
0

Answer:

50 days.

(A+B)'s 1 day work=1/25.

(A+B)'s 15 days work=15/25.

Then B left.

Remaining work=1-15/25=10/25.

So, it takes A 20 days to complete 10/25 part of work.

So, number of days required by A to complete the work = 20*25/10=50.

So, A's 1 day work=1/50.

Had A and B been working for 25 days they would've completed the work.

A's 25 days work=25/50.

So, B's 25 days work =25/50 = 1/2 of total work.

Therefore, to complete the entire work, B needs 25*2=50 days.

Hope this helps.

Answered by alyanas08
0

Answer:

35

Step-by-step explanation:

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