A and b can together complete a work in 10 days, b and c can together complete the work in 12 days while a and c together, takes 15 days to complete the same work. Find the number of days required by c to complete the work alone.
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Work done by both a and b =1/4 (in one day)
Work done by a =1/12 (work done in one day)
1/4–1/12 LCM =12
1/6=1/1/6 (6 multiplies mathematical operation)
Ans =6 daysWork done by both a and b =1/4 (in one day)
Work done by a =1/12 (work done in one day)
1/4–1/12 LCM =12
1/6=1/1/6 (6 multiplies mathematical operation)
Ans =6 days
Work done by a =1/12 (work done in one day)
1/4–1/12 LCM =12
1/6=1/1/6 (6 multiplies mathematical operation)
Ans =6 daysWork done by both a and b =1/4 (in one day)
Work done by a =1/12 (work done in one day)
1/4–1/12 LCM =12
1/6=1/1/6 (6 multiplies mathematical operation)
Ans =6 days
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