Question

A and B can together do a piece of work in 10 days,but A alone can do it in 15 days.How many days would B alne take to do the sane work. Plz in steps

Answer 1

A + B can do the piece of work in 10 days.
(A + B)'s 1 day working capacity =
$\frac{1}{10}$
A can do it in 15 days.....
So, A's 1 day working capacity =
$\frac{1}{15}$
Now, B's 1 day working capacity =
(A + B)'s 1 day working capacity - A's 1 day working capacity
$= \frac{1}{10} - \frac{1}{15} \\ = \frac{3 - 2}{30} \\ = \frac{1}{30}$
Therefore, B's 1 day working capacity =
$\frac{1}{30}$
Hence, B can finish the job alone, in 30 days....

THERE YOU GO!!!.....