A and B can together do a piece of work in 15 days. B alone can do it in 20 days. In how many days
can A alone do it?
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60 days
(A + B)’s 1 day’s work = \frac{1}{15}
B’s 1 day’s work = \frac{1}{20}
∴ A’s 1 day’s work = \frac{1}{15}-\frac{1}{20} = \frac{4-3}{60}= \frac{1}{60}
∴ A alone will do the work in 60 days.
(A + B)’s 1 day’s work = \frac{1}{15}
B’s 1 day’s work = \frac{1}{20}
∴ A’s 1 day’s work = \frac{1}{15}-\frac{1}{20} = \frac{4-3}{60}= \frac{1}{60}
∴ A alone will do the work in 60 days.
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