A and B can together do a piece of work in 15 days. If A alone can do it in 18 days, how long will B alone take to complete the same work?
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Answer:
90 days
Step-by-step explanation:
let days taken by B be x then B' s 1 day work will be 1/x
A' s 1 day work = 1/18
A+B' s 1 day work will be 1/x+1/18
1/15=1/x+1/18
1/15-1/18=1/x
LCM of 15 and 18 is 90
6/90-5/90=1/x
1/90=1/x
therefore A will take 90 days
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