A and B can together do a work in 6 days. If A's 1 day's work is 1 1/2 times the one day's work of B find in how many days each alone can finish the work
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work done by a in 1day is x and b is y
6x +6y =1
x+y=1/6
x=11y/2
11y/2+y=1/6
11y+2y/2=1/6
13y=1/3
y=1/39
x=11/2*1/39
x=11/78
x will do work in78/11 days and y in 39 days
6x +6y =1
x+y=1/6
x=11y/2
11y/2+y=1/6
11y+2y/2=1/6
13y=1/3
y=1/39
x=11/2*1/39
x=11/78
x will do work in78/11 days and y in 39 days
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