Question

A and B combines to form three compounds AB,AB2 and AB3.In 3rd compound if 32g of A combines with 84g of B.In 2nd compound 16g of A will combine with how many gram of B? ​

Answer 1

Explanation:

In case of compound AB

2

:

M

B

=

W

A

ΔT

f

K

f

W

B

×1000

ΔT

f

=2.3K,W

B

=1.0g,W

A

=20.0g,K

f

=5.1KKg/mol

M

B

=

20.0×2.3

5.1×1.0×1000

=110.87 g/mol

In case of compound AB

4

:

ΔT

f

=1.3K,W

B

=1.0g,W

A

=20.0g

M

B

=

20.0×1.3

5.1×1.0×1000

=196.15 g/mol

Let a g/mol and b g/mol be the atomic masses of A and B respectively.

M

AB

2

=a+2b=110.87 .....(i)

M

AB

4

=a+4b=196.15 .......(ii)

Substracting equation (ii) from equation (i), we have

−2b=−85.28

Atomic mass of B is b=42.64.

Substituting the values of b in equation (i), we get

a+2×42.64=110.87

Atomic mass of A is a=25.59 g/mol.

Hence, the atomic mass of a is 25.59 g/mol and b is 42.64 g/mol

Answer 2

Answer:

sorry bro or sis I don't knew the answer