A and B complete a piece of work in 12 days B and C in 16 days a and c in 24 days how long will it take for a, b and c to do the work together
Answers
Answer :-
A, B and C together can complete the work in 32/3 i.e 10 2/3 days.
Explanation :-
A and can complete a piece of work in 12 days
So A and B's 1 day work (A + B) = 1/12
B and C can complete the same work in 16 days
So B and C 1 day work (B + C) = 1/16
A and C can complete the same work in 24 days
So A and C's 1 day work (A + C) = 1/24
We know that
2(A + B + C) = (A + B) + (B + C) + (A + C)
⇒ 2(A + B + C) = (1/12) + (1/16) + (1/24)
Taking LCM
⇒ 2(A + B + C) = (4 + 3 + 2)/48
⇒ 2(A + B + C) = 9/48
⇒ A + B + C = (9/48) ÷ 2
⇒ A + B + C = (9/48) × (1/2)
⇒ A + B + C = 9/96
⇒ A + B + C = 3/32
i.e A , B and C's 1 day work = 3/32
So A, B and C together can complete the work in 32/3 i.e 10 2/3 days.
Further Explanation
According to the given question:-
- A and B complete a piece of work in 12 days B and C in 16 days a and c in 24 days and We have to find that how long will it take for a, b and c to do the work together.
- 12 days is the A time taken to complete a piece of work.
- is the A , B one day work
- 16 days is the B , C time taken to complete the same work and B + C = 1/16 for B , C day and finally the same same is complete by A , C in 24 days so, A + C = 1/24
Therefore,
Now we take LCM
3/32 is the time taken for A , B and C in 1 day frm 10 .2/3 days..