Math, asked by DancingGirlRumpa65, 19 days ago

A and B complete a piece of work in 24 days. B and C do the same work in 36 days ; and A B and C together finish it in 18 days. in how many days will:
i) A alone
2) C alone
3) A and C together complete the work​

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Answers

Answered by moehtesham93
6

Answer:

your answer is in attachment.

Attachments:
Answered by amanraj56
1

Step-by-step explanation:

(A+B) can comple work in 24 days

(A+B) 1day work = 1/24

(B+C) can complete work in 36 days

(B+C) 1day work = 1/36

(A+B+C) can complete work In 18days

(A+B+C) 1day work = 1/18

1) A alone 1day work = (A+B+C)-(B+C)

= 1/18 - 1/36

= (2-1)/36

= 1/36

Hence A can complete work in 36 days.

2) C alone 1day work= (A+B+C)-(A+B)

= 1/18 - 1/24

= (4-3)/72

= 1/72

Hence C can complete work in 72days.

3) (A+C) 1day work= 1/36+1/72

= (2+1)/72

= 3/72

= 1/24

(A+C) can complete work in 24days.

#666

why u have given ur biodata in question

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