A and B complete a work in 6 days.
A alone can do it in 10 days.
If both together can
work in how many days
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Answer:
15 days
Step-by-step explanation:
A+B, one work= 6 days
A alone = 10 days
So,
Work done by A in 1 day = (1/10)th of the total work.
In 6 days, work done by A = (6/10)th of the total work.
So, work done by B in 6 days = {1-(6/10)}= (4/10)
Work done by B in 1 day = (4/10)*(1/6) = (1/15)th of total work.
So Total work can be done by B in 15 days.
Work = LCM(6,10) = 30 units
A does the task(30 units) in 10 days I.e. 3 units/day
A and B do 30 units in 6 days I.e. 5 units/day
5 = 3 + units done by B in a day
Units done by B in a day = 2
Days required by B in a day = Work/units done by B in a day = 30/2 = 15 days
Hope it helps.
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