A and b cycles at the rate of 9km/hr and 10km/ hr respectivly.If the time taken by a to reach a certain distance is 36 min less then the time taken by b to reach the same distance, then the distance travelled by them ?
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lets assume that time taken by a is t hours then time taken by b will be (t+(36/60)) hours
Case of a
9=D/(t+(36/60))
9t+(27/5)=D
5D-45t=27.........(i)
case of b
10=D/t
D-10t=0..........(ii)
performing(ii)x5-(i), we get
5t=27
t=27/5
substituting in (ii) we get
D=54km
the distance travelled by each is 54km
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