Math, asked by diya735, 1 year ago

A and b difference of ages is 16year . 6year ago a was three times



b. What is the present age of a

Answers

Answered by Anonymous
0
According to given condition ,
A - B =16
Since A , 6 years ago was 3 times B's present age
Therefore, A-6 = 3B
Solving both equations simultaneously we get
B = 5 years .
Now , Substituting B = 5 in the above given equation we get A= 21 years .

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